f(x)=(x+4)(2x^2-1)

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Solution for f(x)=(x+4)(2x^2-1) equation:


Simplifying
f(x) = (x + 4)(2x2 + -1)

Multiply f * x
fx = (x + 4)(2x2 + -1)

Reorder the terms:
fx = (4 + x)(2x2 + -1)

Reorder the terms:
fx = (4 + x)(-1 + 2x2)

Multiply (4 + x) * (-1 + 2x2)
fx = (4(-1 + 2x2) + x(-1 + 2x2))
fx = ((-1 * 4 + 2x2 * 4) + x(-1 + 2x2))
fx = ((-4 + 8x2) + x(-1 + 2x2))
fx = (-4 + 8x2 + (-1 * x + 2x2 * x))
fx = (-4 + 8x2 + (-1x + 2x3))

Reorder the terms:
fx = (-4 + -1x + 8x2 + 2x3)
fx = (-4 + -1x + 8x2 + 2x3)

Solving
fx = -4 + -1x + 8x2 + 2x3

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x'.
f = -4x-1 + -1 + 8x + 2x2

Simplifying
f = -4x-1 + -1 + 8x + 2x2

Reorder the terms:
f = -1 + -4x-1 + 8x + 2x2

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